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Java String的序列化总结

发布时间: 2013-04-21 15:31:38 作者: rapoo

Java String的序列化小结

String对我们来说太熟悉了,因为它无处不在,更因为用String可以描述这个世界几乎所有的东西,甚至于为了描述精确的数值都需要String出马(因为计算机眼中的二进制和人类眼中的十进制间总有那么点隔膜)。因为熟悉而变得简单,也容易被忽略。今天记录一下关于String的容易被忽略的两个问题。

字符串重用——节省内存

因为字符串太多,如果能够重用则能够节省很大的内存。首先看下面一个例子:

??????? String string1 = “HELLOHELLO”;

??????? String string2 = “HELLO” + “HELLO”;

上面创建了几个字符串?1 or 2?后者是动态创建的,不过相信JVM可以对其直接优化的,因为编译时已经知道内容了,猜测是一个instance,即同一个char数组。Heapdump出来后观察果然是一个。

String string3 = args[0]+ args[1];

输入参数HELLO HELLO? 字符串变成几个?没错啊,是两个HELLOHELLO了。Dump heap后观察,果然是两个了。(其实不用dump healp,debug也可以看出来,string1和string3中的char[]指向地址是不一样的)。

依此延伸,可以而知由java反序列化而来的那些string也是不一样的。实例如下;

? ??public final static void main(String[] args) throws Exception {

??????? new StringDeserialized().testDescirialized();

??? }

??? public void testDescirialized() throws Exception {

??????? String testString = “HELLOHELLO”;

??????? ObjectOutputStream dataOutStream = new ObjectOutputStream(new FileOutputStream(“./stringdeserialized.data”));

??????? for (int i = 0; i < 1000; i++)

??????????? dataOutStream.writeObject(testString);

??????? dataOutStream.close();

??????? List<String> readAgainList = new ArrayList<String>(100);

??????? for (int i = 0; i < 100; i++) {

??????????? ObjectInputStream dataInputStream = new ObjectInputStream(new FileInputStream(“./stringdeserialized.data”));

??????????? readAgainList.add((String) dataInputStream.readObject());

??????????? dataInputStream.close();

??????? }

???? ???Thread.sleep(Integer.MAX_VALUE);

??? }

?Java String的序列化总结

截图是heap dump出来的,有HELLOHELLO的个数有101个,占用的size>8080。对于JVM的内存使用可参考 http://www.javamex.com/tutorials/memory/object_memory_usage.shtml

问题来了,系统维护的数据大多是字符串信息,比如configserver,而很多的信息都是同一个字符串,那么反复的从网络序列化而来,占用多的Heap。当然自己可以写一个weak hashmap来维护,重用这些字符串。大家知道JVM中有String Pool,使用它无疑最好不过。查找String源码,发现intern()的注释如下:

?? ?* When the intern method is invoked, if the pool already contains a

???? * string equal to this <code>String</code> object as determined by

???? * the {@link #equals(Object)} method, then the string from the pool is

???? * returned. Otherwise, this <code>String</code> object is added to the

???? * pool and a reference to this <code>String</code> object is returned.

于是改变上面一行代码为:

readAgainList.add(((String) dataInputStream.readObject()).intern());

再次Heap dump分析如下,另外可以看出一个包含10个字符的String占用的Heap是80byte:

Java String的序列化总结

?字符串序列化的速度

目前CS处理为了支持所谓的任意类型数据,CS采用了一个技巧,用Swizzle来保存java序列化后的byte类型,Server端无需反序列化就能保存任意类型的data;这样的坏处有两个:通用的Java序列化效率不高;协议不通用,对其他语言支持不行。因为目前的数据信息基本都是String类型,而对对String数据的专门处理,可以通过String内部的byte数组(UTF-8)类表示,这样也便于其他语言解析。可以考虑增加对publish(String)的支持。于是做了如下测试来比较对String不同serialize/deserialize的速率和大小。

结果是writeUTF最小最快,对于100char的String,差距是数量级的相当明显,虽然Swizzle使用了一个技巧,当对同一个swizzle instance多次传输时,无需重复的序列化。

PS:Swizzle简单的说就是把信息包装起来,然后把序列化的byte流缓存起来,这样如果同样的一个信息要推送/发送N次,就无能减少N-1次的序列化时间。

public class CompareSerialization {

??? public String generateTestData(int stringLength) {

??????? Random random = new Random();

??????? StringBuilder builder = new StringBuilder(stringLength);

??????? for (int j = 0; j < stringLength; j++) {

??????????? builder.append((char) random.nextInt(127));

??????? }

??????? return builder.toString();

??? }

??? public int testJavaDefault(String data) throws Exception {

??????? ObjectOutputStream outputStream = null;

??????? ObjectInputStream inputStream = null;

??????? try {

??????????? ByteArrayOutputStream byteArray = new ByteArrayOutputStream();

??????????? outputStream = new ObjectOutputStream(byteArray);

?????????? ?outputStream.writeObject(data);

??????????? outputStream.flush();

??????????? inputStream = new ObjectInputStream(new ByteArrayInputStream(byteArray.toByteArray()));

??????????? inputStream.readObject();

??????????? return byteArray.size();

??????? }

??????? finally {

??????????? outputStream.close();

??????????? inputStream.close();

??????? }

??? }

??? public int testJavaDefaultBytes(String data) throws Exception {

??????? ObjectOutputStream outputStream = null;

??????? ObjectInputStream inputStream = null;

??????? try {

??????????? ByteArrayOutputStream byteArray = new ByteArrayOutputStream();

??????????? outputStream = new ObjectOutputStream(byteArray);

??????????? outputStream.writeBytes(data);

??????????? outputStream.flush();

??????????? inputStream = new ObjectInputStream(new ByteArrayInputStream(byteArray.toByteArray()));

??????????? byte[] bytes = new byte[byteArray.size()];

??????????? inputStream.read(new byte[byteArray.size()]);

??????????? new String(bytes);

?????????? ?return byteArray.size();

??????? }

??????? finally {

??????????? outputStream.close();

??????????? inputStream.close();

??????? }

??? }

??? public int testSwizzle(Swizzle data) throws Exception {

??????? ObjectOutputStream outputStream = null;

??????? ObjectInputStream inputStream = null;

??????? try {

??????????? ByteArrayOutputStream byteArray = new ByteArrayOutputStream();

??????????? outputStream = new ObjectOutputStream(byteArray);

??????????? outputStream.writeObject(data);

??????????? outputStream.flush();

??????????? inputStream = new ObjectInputStream(new ByteArrayInputStream(byteArray.toByteArray()));

??????????? inputStream.readObject();

??????????? return byteArray.size();

??????? }

??????? finally {

??????????? outputStream.close();

??????????? inputStream.close();

??????? }

??? }

??? public int testStringUTF(String data) throws Exception {

??????? ObjectOutputStream outputStream = null;

??????? ObjectInputStream inputStream = null;

??????? try {

??????????? ByteArrayOutputStream byteArray = new ByteArrayOutputStream();

??????????? outputStream = new ObjectOutputStream(byteArray);

??????????? outputStream.writeUTF(data);

??????????? outputStream.flush();

??????????? inputStream = new ObjectInputStream(new ByteArrayInputStream(byteArray.toByteArray()));

??????????? inputStream.readUTF();

??????????? return byteArray.size();

??????? }

??????? finally {

??????????? outputStream.close();

??????????? inputStream.close();

??????? }

??? }

??? public final static void main(String[] args) throws Exception {

??????? CompareSerialization compare = new CompareSerialization();

??????? String data = compare.generateTestData(Integer.parseInt(args[0]));

??????? Swizzle swizzle = new Swizzle(data);

??????? System.out.println(“testJavaDefault size on networking:” + compare.testJavaDefault(data));

??????? System.out.println(“testJavaDefaultBytes size on networking:” + compare.testJavaDefaultBytes(data));

??????? System.out.println(“testStringUTF size on networking:” + compare.testStringUTF(data));

??????? System.out.println(“testSwizzle size on networking:” + compare.testSwizzle(swizzle));

??????? // warm up

??????? for (int i = 0; i < 100; i++) {

??????????? compare.testJavaDefault(data);

??????????? compare.testJavaDefaultBytes(data);

??????????? compare.testStringUTF(data);

??????????? compare.testSwizzle(swizzle);

??????? }

??????? long startTime = System.currentTimeMillis();

??????? for (int i = 0; i < 10000; i++) {

??????????? compare.testJavaDefault(data);

??????? }

??????? long endTime = System.currentTimeMillis();

??????? System.out.println(“testJavaDefault using time:” + (endTime startTime));

??????? startTime = System.currentTimeMillis();

??????? for (int i = 0; i < 10000; i++) {

??????????? compare.testJavaDefaultBytes(data);

??????? }

??????? endTime = System.currentTimeMillis();

??????? System.out.println(“testJavaDefaultBytes using time:” + (endTime startTime));

??????? startTime = System.currentTimeMillis();

??????? for (int i = 0; i < 10000; i++) {

??????????? compare.testStringUTF(data);

??????? }

??????? endTime = System.currentTimeMillis();

??????? System.out.println(“testStringUTF using time:” + (endTime startTime));

??????? startTime = System.currentTimeMillis();

??????? for (int i = 0; i < 10000; i++) {

??????????? compare.testSwizzle(swizzle);

??????? }

??????? endTime = System.currentTimeMillis();

??????? System.out.println(“testSwizzle using time:” + (endTime startTime));

??? }

}

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