数组合并排序问题
本帖最后由 lazygc520 于 2013-06-07 09:37:32 编辑

<?php
$sql = "select DISTINCT b.packageno,a.stock_no from `stock_detail` as a,`kw_manage` as b where a.stock_no = '".$stockno."' and a.cust_no = replace( b.cust_no, ' ', '' )";
$result = mysql_query($sql);
while($row = mysql_fetch_array($result,MYSQL_ASSOC))
{
$sql2 = "select lotno,count(lotno) from `vp_barcode_2d_y` where packageno = '".$row['packageno']."' group by lotno order by lotno asc";
$result2 = mysql_query($sql2);
$var = array();
while($row2 = mysql_fetch_array($result2,MYSQL_NUM))
{

$var[] = array('lotno'=>$row2[0],'count'=>$row2[1]);
}
print_r($var);
}

//echo $a[$k]['5'].'<br />';
?>

得到的结果：

Array
(
    [0] => Array
        (
            [lotno] => 3207
            [count] => 15
        )

)
Array
(
    [0] => Array
        (
            [lotno] => 3207
            [count] => 15
        )

)
Array
(
    [0] => Array
        (
            [lotno] => 3206
            [count] => 12
        )

    [1] => Array
        (
            [lotno] => 3207
            [count] => 3
        )

)
Array
(
    [0] => Array
        (
            [lotno] => 3207
            [count] => 15
        )

)
Array
(
    [0] => Array
        (
            [lotno] => 3207
            [count] => 15
        )

)
Array
(
    [0] => Array
        (
            [lotno] => 3218
            [count] => 15
        )

)
Array
(
    [0] => Array 
 
        (
            [lotno] => 3218
            [count] => 15
        )

)
Array
(
    [0] => Array
        (
            [lotno] => 3218
            [count] => 15
        )

)
Array
(
    [0] => Array
        (
            [lotno] => 3218
            [count] => 15
        )

)
Array
(
    [0] => Array
        (
            [lotno] => 3218
            [count] => 15
        )

)
Array
(
    [0] => Array
        (
            [lotno] => 3218
            [count] => 15
        )

)
Array
(
    [0] => Array
        (
            [lotno] => 3218
            [count] => 15
        )

)
Array
(
    [0] => Array
        (
            [lotno] => 3218
            [count] => 15
        )

)
Array
(
    [0] => Array
        (
            [lotno] => 3218
            [count] => 15
        )

)
Array
(
    [0] => Array
        (
            [lotno] => 3218
            [count] => 15
        )

)
Array
(
    [0] => Array
        (
            [lotno] => 3218
            [count] => 15
        )

)
Array
(
    [0] => Array 
 
        (
            [lotno] => 3218
            [count] => 15
        )

)

如何将这些二维数组合并到一个数组中并按lotno排序？
若lotno相同时，将对应count的值相加。请问下如何处理？
[解决办法]

$sql = "select DISTINCT b.packageno,a.stock_no from `stock_detail` as a,`kw_manage` as b where a.stock_no = '".$stockno."' and a.cust_no = replace( b.cust_no, ' ', '' )";
$result = mysql_query($sql);
$res = array(); //设置一个用于存放结果的数组
while($row = mysql_fetch_array($result,MYSQL_ASSOC))
{
    $sql2 = "select lotno,count(lotno) from `vp_barcode_2d_y` where packageno = '".$row['packageno']."' group by lotno order by lotno asc";
    $result2 = mysql_query($sql2);
    $var = array();
    while($row2 = mysql_fetch_array($result2,MYSQL_NUM))
    {
       if(isset($res[$row2[0]])) $res[$row2[0]]['count'] += $row2[1];
       else $res[$row2[0]] = array('lotno'=>$row2[0],'count'=>$row2[1]);
    }
}
ksort($res); //因键名已处理成 lotno 的值，所以按键名排序就是按 lotno 排序