sql 条件查询对应更新，高手帮下忙。
本帖最后由 gzw13999 于 2013-05-28 01:37:05 编辑

--数据 
declare @tab1 table(id int,mun1 int,mun2 int) 
insert @tab1 
select 1,200,110 union all 
select 2,150,11 union all 
select 3,500,42 union all 
select 4,180,99 union all 
select 5,70,32; 
select * from @tab1

declare @tab2 table(id int,[time] datetime) 
insert @tab2 
select 1,'2013-05-28 01:23:08.467' union all 
select 2,'2013-05-28 01:23:08.467'  union all 
select 3,'2013-05-28 01:23:08.467'  union all 
select 4,'2013-05-28 01:23:08.467'  union all 
select 5,'2013-05-28 01:23:08.467' ; 
select * from @tab2

以上tab1 tab2 两个表 如果tab1 mun2列值大于mun1列值的50% 就把tab2相对应ID的行[time]增加一天时间。

也就是上述tab1表测试数据的1行和4行为值大于50%条件 然后更新tab2 1行和4行[time]增加一天时间
[解决办法]

update @tab2 set time=DATEADD(day,1,time) where id in(
select id from @tab1 where mun2>mun1*0.5)

[解决办法]

declare @tab1 table(id int,mun1 int,mun2 int)

insert @tab1 
select 1,200,110 union all 
select 2,150,11 union all 
select 3,500,42 union all 
select 4,180,99 union all 
select 5,70,32; 

declare @tab2 table(id int,[time] datetime) 

insert @tab2 
select 1,'2013-05-28 01:23:08.467' union all 
select 2,'2013-05-28 01:23:08.467' union all 
select 3,'2013-05-28 01:23:08.467' union all 
select 4,'2013-05-28 01:23:08.467' union all 
select 5,'2013-05-28 01:23:08.467'


update b
 set b.[time]=dateadd(d,1,b.[time])
 from @tab2 b
 inner join @tab1 a on b.id=a.id
 where a.mun2>a.mun1*0.5


select id,[time] from @tab2

/*
id          time
----------- -----------------------
1           2013-05-29 01:23:08.467
2           2013-05-28 01:23:08.467
3           2013-05-28 01:23:08.467
4           2013-05-29 01:23:08.467
5           2013-05-28 01:23:08.467

(5 row(s) affected)
*/