保留表中salary数值最小的。

create table test
(
userName varchar(30),
[month]  varchar(20),
salary   numeric(15,4)
)

insert into test values('adam','201001',4500)
insert into test values('adam','201002',3500)
insert into test values('adam','201003',2500)
go
insert into test values('alice','201001',4500)
insert into test values('alice','201002',3500)
insert into test values('alice','201003',5500)
go
insert into test values('lucy','201001',4500)
insert into test values('lucy','201002',3500)
insert into test values('lucy','201003',9500)
go
insert into test values('emily','201001',10500)
go

有没有好的删除语句，或者这种文档 学习下。 SQL
[解决办法]
delete a from test a, (select userName? min(salary) as salary from test group by username) b
where a.username=b.username and a.salary>b.salary

引用:

Quote: 引用:

delete from test where salary>(select min(salary) from test)

各个名字都要取一个

[解决办法]
delete a
from test a
where exists ( select 1 from test
where username = a.username
and salary < a.salary
)
[解决办法]

delete test from test t1
inner join (select username,min(salary) as salary from test group by username )
t on t.userName = t1.userName and t1.salary > t.salary
[解决办法]

create table test
(
userName varchar(30),
[month]  varchar(20),
salary   numeric(15,4)
)
 
insert into test values('adam','201001',4500)
insert into test values('adam','201002',3500)
insert into test values('adam','201003',2500)
go
insert into test values('alice','201001',4500)
insert into test values('alice','201002',3500)
insert into test values('alice','201003',5500)
go
insert into test values('lucy','201001',4500)
insert into test values('lucy','201002',3500)
insert into test values('lucy','201003',9500)
go
insert into test values('emily','201001',10500)
go


with t as
(select userName,[month],salary,
        row_number() over(partition by userName order by salary) 'rn'  
 
 from test
)
delete from t where rn>1


select userName,[month],salary from test

/*
userName                       month                salary
------------------------------ -------------------- ---------------------------------------
adam                           201003               2500.0000
alice                          201002               3500.0000
lucy                           201002               3500.0000
emily                          201001               10500.0000

(4 row(s) affected)
*/

[解决办法]

delete test from test inner join
(
select userName,min(salary)salary from test group by userName 
)d
on test.userName = d.userName and test.salary > d.salary