select中in和not in
select count(job_Number) from #ddd
select count(job_Number) from #ccc
select count(*) from #ddd d where d.job_Number in (select job_Number from #ccc)
select count(*) from #ddd d where d.job_Number not in (select job_Number from #ccc)
分返回
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在什in有,not in 有呢?
[解决办法]
select count(*) from #ddd d where not exists (select 1 from #ccc where d.job_Number=job_Number)