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ios十六进制跟字符串的相互转换

发布时间: 2013-07-09 09:50:47 作者: rapoo

ios十六进制和字符串的相互转换
NSString *dictString = [dict JSONFragment];//组合成的。
用这个就行了。。。
dictString==={"content":"Sadgfdfg","phoneno":"","email":"1049055935@qq.com"}===?// 十六进制转换为普通字符串的。
+ (NSString *)stringFromHexString:(NSString *)hexString {? //
?? ?
??? char *myBuffer = (char *)malloc((int)[hexString length] / 2 + 1);
??? bzero(myBuffer, [hexString length] / 2 + 1);
??? for (int i = 0; i < [hexString length] - 1; i += 2) {
??????? unsigned int anInt;
??????? NSString * hexCharStr = [hexString substringWithRange:NSMakeRange(i, 2)];
??????? NSScanner * scanner = [[[NSScanner alloc] initWithString:hexCharStr] autorelease];
??????? [scanner scanHexInt:&anInt];
??????? myBuffer[i / 2] = (char)anInt;
??? }
??? NSString *unicodeString = [NSString stringWithCString:myBuffer encoding:4];
??? NSLog(@"------字符串=======%@",unicodeString);
??? return unicodeString;
?? ?
?? ?
}

//普通字符串转换为十六进制的。

+ (NSString *)hexStringFromString:(NSString *)string{
??? NSData *myD = [string dataUsingEncoding:NSUTF8StringEncoding];
??? Byte *bytes = (Byte *)[myD bytes];
??? //下面是Byte 转换为16进制。
??? NSString *hexStr=@"";
??? for(int i=0;i<[myD length];i++)
?????? ?
??? {
??????? NSString *newHexStr = [NSString stringWithFormat:@"%x",bytes[i]&0xff];///16进制数
?????? ?
??????? if([newHexStr length]==1)
?????????? ?
??????????? hexStr = [NSString stringWithFormat:@"%@0%@",hexStr,newHexStr];
?????? ?
??????? else
?????????? ?
??????????? hexStr = [NSString stringWithFormat:@"%@%@",hexStr,newHexStr];
??? }
??? return hexStr;
}

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