求帮忙解释下这个C++程序

  4 #include <iostream>
  5 #include <stdio.h>
  6 #include <string.h>
  7 #include <math.h>
  8
  9 using namespace std;
 10
 11 char* ieee32(long long*, long long*, char*, char*);
 12
 13 int main()
 14 {
 15         char input[256],IEEE32[10],IEEE64[18];
 16         char *waypoint, *decimal;
 17         int i=0;
 18         long long number=0,digits=0;
 19         int sign;
 20         cout << "Number: ";
 21         cin >> input;
 22         waypoint=strtok(input, ".");
 23         if (input[0]-'-' == 0){
 24                 input[0]='0';
 25                 sign=1;
 26                 for (i=0;i<strlen(waypoint);i++){
 27                         number+=((input[i]-'0')*(pow(10,(strlen(waypoint)-i-1))));
 28                 }
 29         }
 30         else{
 31                 sign=0;
 32                 for (i=0;i<strlen(waypoint);i++){
 33                         number+=((input[i]-'0')*(pow(10,(strlen(waypoint)-i-1))));
 34                 }
 35                 cout << waypoint << endl; 
 
 36         }
 37         decimal=strtok(NULL, "\0");
 38         for (i=0;i<strlen(decimal);i++){
 39                 digits+=((decimal[i]-'0')*(pow(10,(strlen(decimal)-i-1))));
 40         }
 41         ieee32(&number,&digits,waypoint,decimal);
 42         return 0;
 43 }
 44
 45 char* ieee32(long long* number, long long* digits, char* waypoint, char* decimal)
 46 {
 47         char binary1[1000],binary2[1000];
 48         int temp,carry;
 49         int i;
 50         //for (i=0;i<strlen(waypoint);i++){
 51         //      temp=(*number)&1;
 52         //      cout << temp << endl;
 53         //}
 54         cout << waypoint << endl;
 55         cout << *digits << endl;
 56         cout << *number << endl;
 57         cout << *digits << endl;
 58         return 0;
 59 }
 60

我不理解为什么54行waypoint不需要指针而55行的digits需要指针，求大神帮忙解释
[解决办法]
这主要是看cout要输出什么，waypoint表示字符串，而*digits表示一维long数组。