在这样的字符串中，如何提取前面的数字？
我现在字段里有这样的字符串，如:1 x535,1 x 535L,1x 5204,2 x 4345这样的字符串里，如何提取得到最前面的数字。因为这个数字后跟空格，再跟x，再有空格？是不是字符串匹配的内容？
[解决办法]
试试：CStr(Val("1 x535"))
[解决办法]

Private Sub Form_Load()
    Dim dic As Object, tmp
    Dim strData As String
    Dim reg As Object
    Dim matchs As Object, match As Object

    strData = "1 x 5503,2x 3402" & vbCrLf & _
              "2 x 231" & vbCrLf & _
              "1 x 4602" & vbCrLf & _
              "1 x 2121" & vbCrLf & _
              "1 x 1290" & vbCrLf & _
              "2 x 5503" & vbCrLf & _
              "1 x 4602" & vbCrLf & _
              "1 x 2121" & vbCrLf & _
              "1 x 231"

    Set dic = CreateObject("scripting.dictionary")
    Set reg = CreateObject("vbscript.regExp")
    reg.Global = True
    reg.Pattern = "(\d+)\s*x\s*(\d+)"
    Set matchs = reg.Execute(strData)
    For Each match In matchs
        dic(match.SubMatches(1)) = dic(match.SubMatches(1)) + Val(match.SubMatches(0)) 
 
    Next
    
    For Each tmp In dic.keys
        Debug.Print tmp & vbTab & dic(tmp)
    Next
End Sub

输出：
5503 3
3402 2
231 3
4602 2
2121 2
1290 1

[解决办法]
那就只好代码逐项处理了。

下面是一个借助 ListBox 统计的例子，假定数据已经放在 TextBox 中。

Option Explicit
Private Declare Function SendMessagebyString Lib _
"user32" Alias "SendMessageA" (ByVal hWND As Long, _
ByVal wMsg As Long, ByVal wParam As Long, _
ByVal lParam As String) As Long

Private Const LB_FINDSTRINGEXACT = &H1A2

Private Sub Command1_Click()
Dim strData As String
Dim strLine() As String, strItem() As String, strPara() As String
Dim i As Long, j As Long, n As Long

    strData = Text1
    
    strData = Replace(strData, "X", "x")
    strData = Replace(strData, " ", "")
    
    strLine = Split(strData, vbCrLf)
    
    List1.Clear
    For i = 0 To UBound(strLine)
        strItem = Split(strLine(i), ",")
        
        For j = 0 To UBound(strItem)
            strPara = Split(strItem(j), "x")
            
            If UBound(strPara) = 1 Then
                n = SendMessagebyString(List1.hWND, LB_FINDSTRINGEXACT, -1, strPara(1))
                
                If n = -1 Then
                    List1.AddItem strPara(1) 
 
                    List1.ItemData(List1.NewIndex) = Val(strPara(0))
                Else
                    List1.ItemData(n) = List1.ItemData(n) + Val(strPara(0))
                End If
            End If
        Next j
    Next i
        
    'show result
    For i = 0 To List1.ListCount - 1
        Debug.Print List1.List(i), List1.ItemData(i)
    Next i
End Sub

Private Sub Form_Load()
    Text1 = "1 x 5503,2x 3402" & vbCrLf & _
        "2 x 231" & vbCrLf & _
        "1 x 4602" & vbCrLf & _
        "1 x 2121" & vbCrLf & _
        "1 x 1290" & vbCrLf & _
        "2 x 5503" & vbCrLf & _
        "1 x 4602" & vbCrLf & _
        "1 x 2121" & vbCrLf & _
        "1 x 231"
    List1.Visible = False
End Sub

5503           3 
3402           2 
231            3 
4602           2 
2121           2 
1290           1