C++中迭代器做形参，
//下面是代码:问题在注释里面。我是个初学者，望大家不吝赐教

#include<iostream>
#include<algorithm>
#include<list>
using namespace std;


template<class T>
void output(list<T>& coll,list<int>::iterator& pos)//当我把此处int改成T后，就编译错误，为什么此处不支持模板呢？
{
for(pos=coll.begin();pos!=coll.end();++pos)
{
cout<<*pos<<" ";
}

}

int main()
{
list<int> coll1;

list<int>::iterator pos;
coll1.push_back(30);
coll1.push_back(0);
coll1.push_back(2);
coll1.push_back(9);
coll1.push_back(2);
coll1.push_back(1);
coll1.push_back(1);
coll1.push_back(87);


output(coll1,pos);


return 0;
}

[解决办法]
typename list<T>::iterator