SQLserver 如何分组合计？
例如，有表名称列W_anme，数量列w_sl
W_anme w_sl
---------------------------
aa 3
bb 6
cc 2
aa 1
bb 8
bb 5
---------------------------
想得到
W_anme w_sl
---------------------------
aa 4
bb 19
cc 2
---------------------------

这个SQL语句怎么写？
[解决办法]

declare @t table (W_anme varchar(2),w_sl int)
insert into @t
select 'aa',3 union all
select 'bb',6 union all
select 'cc',2 union all
select 'aa',1 union all
select 'bb',8 union all
select 'bb',5

select W_anme,sum(w_sl) w_sl from @t group by W_anme
/*
W_anme w_sl
------ -----------
aa     4
bb     19
cc     2

*/

[解决办法]

select W_anme,sum(w_sl) w_sl from 你的表名 group by W_anme

[解决办法]
select W_anme,sum(w_sl) as 别名 from TB group by W_anme
[解决办法]

引用:

上面的问题，怎么办

declare @t table (W_anme varchar(2),w_sl int,c varchar(20),d int)
insert into @t
select 'aa',3,'c',2 union all
select 'bb',6,'c',2 union all
select 'cc',2,'c',2 union all
select 'aa',1,'c',2 union all
select 'bb',8,'c',2 union all
select 'bb',5,'c',2

select W_anme, w_sl=COUNT(w_sl),c,d from @t
group by W_anme,c,d

注意红色对应就可以了
[解决办法]
select W_anme,sum(w_sl) w_sl from tbl group by W_anme
select 中的列要显示的话，就必须在group by 后面加上去
[解决办法]
不知道楼主想要什么，建议先了解分组聚合的用法。楼主的要求可以下面语句

select id,w_anme,sum(w_sl) over(partition by w_anme) from tab

[解决办法]
--只按W_name分组的话，你的ID要多选一一下：

declare @t table (W_name varchar(2),w_sl INT, id INT)
insert into @t
select 'aa',3, 1 union all
select 'bb',6, 2 union all
select 'cc',2, 3 union all
select 'aa',1, 4 union all
select 'bb',8, 5 union all
select 'bb',5, 6

SELECT B.*, A.W_SL FROM
(SELECT W_name, w_sl=SUM(w_sl) FROM @t GROUP BY W_name) a
CROSS APPLY
(SELECT TOP(1) * FROM @t WHERE W_name = a.W_name ORDER BY id DESC) b --想取哪一条，自己随意