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求SQL 话语以逗号为分隔

发布时间: 2013-08-13 16:43:28 作者: rapoo

求SQL 语句,以逗号为分隔
DECLARE @xx VARCHAR(100) ,
@yy VARCHAR(100)

set @xx='ds,B,cee,d,' --以逗号为分隔的字符串
set @yy='122,24,3,4,'


怎么写一个循环语句,得到

当输出ds时,同时输出122
当输出B时,同时输出24


一一对应,输出的值用做调用
[解决办法]
这个需要建个函数

/*
DROP FUNCTION dbo.Split
SELECT dbo.Split
*/
CREATE FUNCTION dbo.Split
(
@SplitString varchar(8000),-- nvarchar(4000)
@Separator varchar(2) = ','
)
RETURNS @SplitStringsTable TABLE
(
[id] int identity(1,1),
[value] varchar(8000)-- nvarchar(4000)
)
AS
BEGIN
DECLARE @CurrentIndex int;
DECLARE @NextIndex int;
DECLARE @ReturnText varchar(8000);-- nvarchar(4000)
SELECT @CurrentIndex=1;
WHILE(@CurrentIndex<=len(@SplitString))
BEGIN
SELECT @NextIndex=charindex(@Separator,@SplitString,@CurrentIndex);
IF(@NextIndex=0 OR @NextIndex IS NULL)
SELECT @NextIndex=len(@SplitString)+1;

SELECT @ReturnText=substring(@SplitString,@CurrentIndex,@NextIndex-@CurrentIndex);

INSERT INTO @SplitStringsTable([value])
VALUES(@ReturnText);

SELECT @CurrentIndex=@NextIndex+1;
END
RETURN;
END


DECLARE @xx VARCHAR(100) ,@yy VARCHAR(100)
set @xx='ds,B,cee,d,' --以逗号为分隔的字符串
set @yy='122,24,3,4,'

declare @s varchar(10)
set @s='ds'

select b.value


from dbo.split(@xx,',') a
inner join dbo.split(@yy,',') b on a.id=b.id
where a.value=@s


/*
122
*/

DECLARE @xx VARCHAR(100) ,@yy VARCHAR(100)
set @xx='ds,B,cee,d,' --以逗号为分隔的字符串
set @yy='122,24,3,4,'

declare @s varchar(10)
set @s='B'

select b.value
from dbo.split(@xx,',') a
inner join dbo.split(@yy,',') b on a.id=b.id
where a.value=@s

/*
24
*/


[解决办法]
DECLARE  @xx VARCHAR(100) ,
@yy VARCHAR(100)

set @xx='ds,B,cee,d,'
set @yy='122,24,3,4,'

SELECT b.*
FROM
(
SELECT
xx=CONVERT(XML, '<root><v>'+replace(xx,',','</v><v>')+'</v></root>'),
yy=CONVERT(XML, '<root><v>'+replace(yy,',','</v><v>')+'</v></root>')
FROM (SELECT xx = LEFT(@xx, LEN(@xx)-1), yy=LEFT(@yy, LEN(@yy)-1)) t
) a
OUTER APPLY
(
SELECT m.rowid,m.xx,n.yy FROM
(
SELECT rowid = ROW_NUMBER() OVER(ORDER BY GETDATE()), xx = C.v.value('.','NVARCHAR(MAX)')
FROM a.xx.nodes('/root/v') C(v)
) m
INNER join
(
SELECT rowid = ROW_NUMBER() OVER(ORDER BY GETDATE()), yy = C.v.value('.','NVARCHAR(MAX)')
FROM a.yy.nodes('/root/v') C(v)
) n
ON m.rowid = n.rowid
) b
/*
rowidxxyy
1ds122
2B24
3cee3
4d4
*/

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