java报错
先上代码

import java.net.URL;  
import java.io.*;  
import org.w3c.tidy.Tidy;   
  
public class TestHTML2XML {  
private String url;   
private String outFileName;   
private String errOutFileName;   
  
public TestHTML2XML(String url, String outFileName, String  
errOutFileName) {   
this.url = url;   
this.outFileName = outFileName;   
this.errOutFileName = errOutFileName;   
}  
  
public void convert() {   
URL u;   
BufferedInputStream in;   
FileOutputStream out;   
  
Tidy tidy = new Tidy();   
  
//Tell Tidy to convert HTML to XML  
tidy.setXmlOut(true);   
  
try {   
//Set file for error messages  
tidy.setErrout(new PrintWriter(new FileWriter(errOutFileName), true));   
u = new URL(url);   
  
//Create input and output streams  
in = new BufferedInputStream(u.openStream());   
out = new FileOutputStream(outFileName);   
  
//Convert files  
tidy.parse(in, out);   
  
//Clean up  
in.close();  
out.close();  
  
} catch (IOException e) {   
System.out.println(this.toString() + e.toString());   
}   
}   
  
public static void main(String[] args) {  
/*  
* Parameters are: 
* URL of HTML file 
* Filename of output file 
* Filename of error file  
*/  
String one="00001.html";
String two="real.xml";
String three="error.xml";
TestHTML2XML t = new TestHTML2XML(one, two, three);  
t.convert();  
}  
}  

TestHTML2XML@6d632c2djava.net.MalformedURLException: no protocol: 00001.html

Java String
[解决办法]
文件路径没写完整。 需要包含协议头

比如 http 或者 你是本地文件的话需要 file:///+ 文件路径