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二个查询结果不一样哪位分析下哈哈

发布时间: 2013-08-24 13:17:55 作者: rapoo

2个查询结果不一样,哪位分析下,哈哈


szy_temp里面有重复的数据

insert into szy_max
select gdsid,kqbh,gys,max(lastmodified)
from szy_temp
group by gdsid,kqbh,gys



查询1:

delete szy_temp
from szy_temp a,szy_max b
where a.gdsid = b.gdsid and a.kqbh = b.kqbh and a.gys = b.gys and a.lastmodified < b.lastmodified

select * from szy_temp


查询2:

select *
from szy_temp a,szy_max b
where a.gdsid = b.gdsid and a.kqbh = b.kqbh and a.gys = b.gys and a.lastmodified = b.lastmodified


[解决办法]
下面的查询1和2的结果是一样的:


--szy_temp里面有重复的数据

declare @szy_temp table(gdsid int,kqbh int,gys int,lastmodified datetime)
declare @szy_max table(gdsid int,kqbh int,gys int,lastmodified datetime)

insert into @szy_temp
values(1,1,1,'2013-01-01 00:00:01'),
(1,1,1,'2013-01-01 00:00:05')


insert into @szy_max
select gdsid,kqbh,gys,max(lastmodified)
from @szy_temp
group by gdsid,kqbh,gys



--查询1:

delete @szy_temp
from @szy_temp a,@szy_max b
where a.gdsid = b.gdsid and a.kqbh = b.kqbh and a.gys = b.gys and a.lastmodified < b.lastmodified

select * from @szy_temp


--查询2:

select a.*
from @szy_temp a,@szy_max b
where a.gdsid = b.gdsid and a.kqbh = b.kqbh and a.gys = b.gys and a.lastmodified = b.lastmodified


[解决办法]
--楼主还是找一条异常的数据,分析之 


--查询1:
SELECT *
from szy_temp a
INNER JOIN
(
select gdsid,kqbh,gys,lastmodified=max(lastmodified)
from szy_temp
group by gdsid,kqbh,gys
) b
on a.gdsid = b.gdsid and a.kqbh = b.kqbh and a.gys = b.gys and a.lastmodified < b.lastmodified

--查询2:
select *
from szy_temp a
INNER JOIN
(
select gdsid,kqbh,gys,lastmodified=max(lastmodified)
from szy_temp
group by gdsid,kqbh,gys
) b
on a.gdsid = b.gdsid and a.kqbh = b.kqbh and a.gys = b.gys and a.lastmodified = b.lastmodified

--查询3:再试试这个SQL,看看结果如何?
SELECT * FROM szy_temp a
WHERE NOT EXISTS
(
SELECT 1
FROM szy_temp b
WHERE a.gdsid = b.gdsid and a.kqbh = b.kqbh and a.gys = b.gys and b.lastmodified > a.lastmodified
)

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