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关于ajax解析json解决方案

发布时间: 2013-08-26 12:17:40 作者: rapoo

关于ajax解析json

  $.ajax({
type:"post",
url:"SecondServlet",
data:"&pid=1",
//dataType:"json",
success: function(data){
;
var d=data;
alert(d);
alert(d.mydata[0].usernum);
//$("p").append(d.mydate[1].teamnum);

},
error:function(err){alert("err");}

其中alert(d)显示的是{"mydata":[{"usernum":16789},{"teamnum":1970},{"resourcenum":108828}]}
而错误提示为Uncaught TypeError: Cannot read property '0' of undefined
我尝试着这样写
<script>
$(document).ready(function(){
var user =
{
"username":"andy",
"age":20,
"info": { "tel": "123456", "cellphone": "98765"},
"address":
[
{"city":"beijing","postcode":222333},
{"city":"newyork","postcode":"555666"}
]
}


//alert(user.address[0]);
alert(user.address[0].postcode);
})</script>
直接把json写在js中可行能成功,但像之前从servlet拿到的data却不行,拿到的data还是jaon格式的。
ps:我已经把json.js 和jq.js导入了
求大神帮助 JSON
[解决办法]
success: function(data){
var d=eval(data); //json字符串转换成js对象
alert(data);
alert(d.mydata[0].usernum);
}
[解决办法]
  $.ajax({
type:"post",
url:"SecondServlet",
data:"&pid=1",
dataType:"json",


success: function(data){
;
var d=data;
alert(d);//[object Object]
alert(d.mydata[0].usernum);
//$("p").append(d.mydate[1].teamnum);

},
error:function(err){alert("err");}


  $.ajax({
type:"post",
url:"SecondServlet",
data:"&pid=1",
//dataType:"json",
success: function(data){
;
var d=data;
alert(d);//{"mydata":[{"usernum":16789},{"teamnum":1970},{"resourcenum":108828}]}
d = eval('(' + d + ')');
alert(d.mydata[0].usernum); //16789


//$("p").append(d.mydate[1].teamnum);

},
error:function(err){alert("err");}

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