请问j2ee的目录架构是怎么样的？如何运行？
我的目录架构这样子对吗？
我想要运行form.html，再通过html的提交到HelloServlet.java这个servlet中，如何运行？
我的form.html:
<?xml version="1.0" encoding="UTF-8" ?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>Insert title here</title>
</head>
<body>
<form action="hello.avi" method="post">
名称：<input type="text" name="user" /><br />
密码：<input type="password" name="passwd" /><br /><br />
<input type="submit" name="login" value="送出" />
</form>
</body>
</html>
HelloServlet.java:
架构 JavaEE HTML String Servlet
package cc.openhome;
import java.io.BufferedReader;
import java.io.PrintWriter;
import java.io.IOException;
import java.util.Enumeration;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
/**
* Servlet implementation class HelloServlet
*/
@WebServlet(
name="Hello",
urlPatterns={"/hello.avi"},
loadOnStartup=1
)
public class HelloServlet extends HttpServlet {
private static final long serialVersionUID = 1L;
/**
* @see HttpServlet#HttpServlet()
*/
public HelloServlet() {
super();
// TODO Auto-generated constructor stub
}
/**
* @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
*/
@Override
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
String body = readBody(request);
PrintWriter out = response.getWriter();
out.println("<html>");
out.println("<head>");
out.println("<title>Servlet BodyView</title>");
out.println("</head>");
out.println("<body>" + body + "</body>");
out.println("</html>");
}
private String readBody(HttpServletRequest request) throws IOException {
BufferedReader reader = request.getReader();
String input = null;
String requestBody = "";
while ((input = reader.readLine()) != null) {
requestBody += input + "<br />";
}
return requestBody;
}
}
[解决办法]
form.html放在WEB-INF是不能通过浏览器直接访问的。必须通过servlet访问它。如果要直接访问，必须把它放在WEB-INF外面也就是WebContent下。