一个加密的JS文件求高手解密
本帖最后由 feitian2008sx 于 2013-09-10 11:14:00 编辑 解密后的代码如下
js解密?js加密破解
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1k},\'\\1g\\y\\u\\X\\1f\\e\\m\\c\':Z(){1a($$(b$[3q]).S.W==b$[3t]){$$(b$[3s]).S.W=b$[3m]}1h{$$(b$[3p]).S.W=b$[3o]}},\'\\2p\\k\\B\\m\':Z(1r,n){J 2o=$$(b$[3u]+1r).S.W;1H(J i=1b;i<=n;i++){$$(b$[3A]+i).2d=b$[3z];$$(b$[3w]+i).S.W=b$[3l]};$$(b$[2U]+1r).2d=b$[3h];1a(2o==b$[3k]){$$(b$[3j]+1r).S.W=b$[3e]}1h{$$(b$[3d]+1r).S.W=b$[3g]}},\'\\2i\\q\\m\\c\\k\\l\\l\':Z(){J 2n=1v(b$[3f]+h.1A);$$(b$[3Z]).1n=b$[3Y]+h.1A+b$[4b]+2n+b$[4a]+h.1C+b$[3V];$$(b$[3U]).S.W=b$[3X]},\'\\1s\\c\\D\\l\':Z(){1u.1D(b$[3W])},\'\\P\\l\\k\\C\':Z(){h.4c();h.2f=h.G.1K[1b];h.2h=h.G.1K[I];h.2j=h.G.1K[1p];J 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[解决办法]
var killErrors = function(value){return true};
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window.onerror = killErrors;
var $$ = function(value){return document.getElementById(value)};
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}else {
var list_show=_$[19];
}
if(this.NextWebPage){
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}else {
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}
$$(_$[20]).innerHTML=_$[21]+this.LastWebPage+_$[22]+NextWebPage+_$[23];
$$(_$[24]).innerHTML=_$[25]+this.ListUrl+_$[26]+this.ListName+_$[27]+this.VodName+_$[28]+this.UrlName+_$[29];
$$(_$[30]).innerHTML=_$[31];
$$(_$[32]).innerHTML=_$[33]+this.Buffer+_$[34]+this.Height+_$[35]+$Showhtml();
$$(_$[36]).style.height=this.Height+_$[37];
$$(_$[38]).innerHTML=_$[39]+list_show+_$[40]+this.Height+_$[41]+this.CreateList()+_$[42];
document.write(_$[43]+_$[44]+_$[45]);
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},"CreateList":function(){
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h2class=_$[50];
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var sub_on;
var html_sub;
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if(this.Sid==i&&this.Pid==(j+1)){
var li_on=_$[56];
}else {
li_on=_$[57];
}
html_sub+=_$[58]+href+_$[59]+this.UrlJson.Data[i].playurls[j][1]+_$[60]+li_on+_$[61]+this.UrlJson.Data[i].playurls[j][0]+_$[62];
}
html_sub+=_$[63];
html+=_$[64]+i+_$[65]+h2class+_$[66];
html+=_$[67]+i+_$[68]+(this.UrlJson.Data.length-1)+_$[69]+eval(_$[70]+this.UrlJson.Data[i].playname)+_$[71];
html+=html_sub;
html+=_$[72];
}
return html;
},"ShowList":function(){
if($$(_$[73]).style.display==_$[74]){
$$(_$[75]).style.display=_$[76];
}else {
$$(_$[77]).style.display=_$[78];
}
},"Tabs":function(no,n){
var subdisply=$$(_$[79]+no).style.display;
for(var i=0;i<=n;i++){
$$(_$[80]+i).className=_$[81];
$$(_$[82]+i).style.display=_$[83];
}
$$(_$[84]+no).className=_$[85];
if(subdisply==_$[86]){
$$(_$[87]+no).style.display=_$[88];
}else {
$$(_$[89]+no).style.display=_$[90];
}
},"Install":function(){
var downurl=eval(_$[91]+this.PlayerName);
$$(_$[92]).innerHTML=_$[93]+this.PlayerName+_$[94]+downurl+_$[95]+this.Height+_$[96];
$$(_$[97]).style.display=_$[98];
},"Html":function(){
document.write(_$[99]);
},"Play":function(){
this.Html();
this.VodName=this.UrlJson.Vod[0];
this.ListName=this.UrlJson.Vod[1];
this.ListUrl=this.UrlJson.Vod[2];
var URL=this.ParentUrl.match(/\d+.*/g)[0].match(/\d+/g);
this.Id=URL[(URL.length-3)]*1;
this.Sid=URL[(URL.length-2)]*1;
this.Pid=URL[(URL.length-1)]*1;
this.Pid=Math.min(this.Pid,this.UrlJson.Data[this.Sid].playurls.length);
this.PlayerName=this.UrlJson.Data[this.Sid].playname;
if(this.UrlJson.Data[this.Sid].servername){
this.ServerUrl=eval(_$[100]+this.UrlJson.Data[this.Sid].servername);
}
this.Url=this.ServerUrl+this.UrlJson.Data[this.Sid].playurls[(this.Pid-1)][1];
this.UrlName=this.UrlJson.Data[this.Sid].playurls[(this.Pid-1)][0];
this.LastPid=Math.max(Math.abs(this.Pid-1),1);
this.LastWebPage=this.UrlJson.Data[this.Sid].playurls[this.LastPid-1][2];
this.NextPid=Math.min(this.Pid+1,this.UrlJson.Data[this.Sid].playurls.length);
this.NextUrl=this.ServerUrl+this.UrlJson.Data[this.Sid].playurls[this.NextPid-1][1];
this.NextUrlName=this.UrlJson.Data[this.Sid].playurls[this.NextPid-1][0];
if(this.Url==this.NextUrl){
this.NextWebPage=_$[101];
}else {
this.NextWebPage=this.UrlJson.Data[this.Sid].playurls[this.NextPid-1][2];
}
document.write(_$[102]+_$[103]+this.Root+_$[104]+this.PlayerName+_$[105]+_$[106]);
}};