字符串的反转五种方法

#include<iostream>#include<string>using namespace std;char *reverse1(  char *str, int len){    if(len<=1)       //边界条件return str;char temp = *str;*str = *(str+len-1);*(str+len-1) = temp;    return (reverse1( str+1, len-2)-1);}char *reverse2( const char *str){    char *temp = new char[strlen(str)+1];strcpy(temp, str);    //会复制\0int len = strlen(str);for( int i=0; i<len/2; i++){char ch = temp[i];temp[i] = temp[len-i-1];temp[len-i-1] = ch;}//temp[len] = '\0';return temp;}char *reverse3( const char *str){char *temp = new char[strlen(str)+1];strcpy(temp, str);int len = strlen(str);char *head = temp;char *rear = temp+len-1;while(head<rear){        char ch = *head;*head = *rear;*rear = ch;++head;        --rear;}//temp[len] = '\0';return temp;}char *reverse4( const char *str){char *temp = new char[strlen(str)+1];strcpy(temp, str);int len = strlen(str);char *head = temp;char *rear = temp+len-1;while(head<rear){        *head = *head+*rear;*rear = *head-*rear;*head = *head-*rear;++head;        --rear;}return temp;}char *reverse5( const char *str){    char *temp = new char[strlen(str)+1];strcpy(temp, str);int len = strlen(str);char *head = temp;char *rear = temp+len-1;while(head<rear){*head^=*rear;*rear^=*head;*head^=*rear;++head;--rear;}return temp;}int main(){   char str[7] = "123456";cout<<reverse2(str)<<endl;cout<<reverse3(str)<<endl;cout<<reverse4(str)<<endl;cout<<reverse5(str)<<endl;cout<<reverse1(str, 6)<<endl;    return 0;}

2楼mazhaojuan昨天 17:51

无说明的代码！

1楼u011747022昨天 15:08

别人的代码不好看得懂