Struts2+Jquery实现ajax并返回json类型数据
摘要： 主要实现步骤如下： 1、JSP页面使用脚本代码执行ajax请求 2、Action中查询出需要返回的数据，并转换为json类型模式数据 3、配置struts.xml文件 4、页面脚本接受并处理数据
json需要的包：
commons-logging-*.jar在导入struts核心包的时候就导入了，所以导入json包的时候可以去掉这个包
页面效果：
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json_demo.jsp页面（该页面引用了jquery文件，我用的版本是jquery-1.8.2.js，如果使用版本不同，请自行修改）：
04<html>05<head>06<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">07<title>Simpleton Demo | struts+ajax返回json类型数据</title>08?09<link rel="shortcut icon" type="image/x-icon" href="images/Icon.png" />10<link rel="stylesheet" type="text/css" href="styles/base.css" />11?12</head>13<body background="images/bg.gif">14??? 15??? <div id="div_json">16??????? <h5>录入数据</h5>17??????? <br />18??????? <form action="#" method="post">19??????????? <label for="name">姓名：</label><input type="text" name="name" />20??????????? <label for="age">年龄：</label><input type="text" name="age" />21??????????? <label for="position">职务：</label><input type="text" name="position" />22??????????? <input type="button" class="btn" value="提交结果"/>23??????? </form>24??????? <br />25??????? <h5>显示结果</h5>26??????? <br />27??????? <ul>28??????????? <li>姓名：<span id="s_name">赞无数据</span></li>29??????????? <li class="li_layout">年龄：<span id="s_age">暂无数据</span></li>30??????????? <li class="li_layout">职务：<span id="s_position">暂无数据</span></li>31??????? </ul>32??? </div>33??? 34??? <div id="authorgraph"><img alt="" src="images/autograph.gif"></div>35??? 36??? <script type="text/javascript" src="scripts/jquery-1.8.2.js"></script>37??? <script type="text/javascript">38??????? 39??????? /* 提交结果，执行ajax */40??????? function btn(){41??????????? 42??????????? var $btn = $("input.btn");//获取按钮元素43??????????? //给按钮绑定点击事件44??????????? $btn.bind("click",function(){45??????????????? 46??????????????? $.ajax({47??????????????????? type:"post",48??????????????????? url:"excuteAjaxJsonAction",//需要用来处理ajax请求的action,excuteAjax为处理的方法名，JsonAction为action名49??????????????????? data:{//设置数据源50??????????????????????? name:$("input[name=name]").val(),51??????????????????????? age:$("input[name=age]").val(),52??????????????????????? position:$("input[name=position]").val()//这里不要加","? 不然会报错，而且根本不会提示错误地方53??????????????????? },54??????????????????? dataType:"json",//设置需要返回的数据类型55??????????????????? success:function(data){56??????????????????????? var d = eval("("+data+")");//将数据转换成json类型，可以把data用alert()输出出来看看到底是什么样的结构57??????????????????????? //得到的d是一个形如{"key":"value","key1":"value1"}的数据类型，然后取值出来58??????????????????????? 59??????????????????????? $("#s_name").text(""+d.name+"");60??????????????????????? $("#s_age").text(""+d.age+"");61??????????????????????? $("#s_position").text(""+d.position+"");62??????????????????????? 63??????????????????? },64??????????????????? error:function(){65??????????????????????? alert("系统异常，请稍后重试！");66??????????????????? }//这里不要加","67??????????????? });68??????????? });69??????? }70??? 71??????? /* 页面加载完成，绑定事件 */72??????? $(document).ready(function(){?????????? 73??????????? btn();//点击提交，执行ajax74??????? });75??? </script>76</body>77</html>JsonAction.java代码
查看源码?打印?01package com.simpleton.demo.action;02?03import java.util.HashMap;04import java.util.Map;05?06import javax.servlet.http.HttpServletRequest;07?08import net.sf.json.JSONObject;09?10import org.apache.struts2.interceptor.ServletRequestAware;11?12import com.opensymphony.xwork2.ActionSupport;13?14public class JsonAction extends ActionSupport implements ServletRequestAware{15??? private static final long serialVersionUID = 1L;16??? 17??? private HttpServletRequest request;18??? private String result;19?20??? public void setServletRequest(HttpServletRequest arg0) {21??????? this.request = arg0;22??? }23??? public String getResult() {24??????? return result;25??? }26??? public void setResult(String result) {27??????? this.result = result;28??? }29??? 30??? /**31???? * 处理ajax请求32???? * @return SUCCESS33???? */34??? public String excuteAjax(){35??????? 36??????? try {37??????????? //获取数据38??????????? String name = request.getParameter("name");39??????????? int age = Integer.parseInt(request.getParameter("age")); 40??????????? String position = request.getParameter("position");41??????????? 42??????????? //将数据存储在map里，再转换成json类型数据，也可以自己手动构造json类型数据43??????????? Map<String,Object> map = new HashMap<String,Object>();44??????????? map.put("name", name);45??????????? map.put("age",age);46??????????? map.put("position", position);47??????????? 48??????????? JSONObject json = JSONObject.fromObject(map);//将map对象转换成json类型数据49??????????? result = json.toString();//给result赋值，传递给页面50??????? } catch (Exception e) {51??????????? e.printStackTrace();52??????? }53??????? return SUCCESS;54??? }55?56?57??? 58}struts.xml中
查看源码?打印?01<?xml version="1.0" encoding="UTF-8"?>02<!DOCTYPE struts PUBLIC03??? "-//Apache Software Foundation//DTD Struts Configuration 2.1.7//EN"04??? "http://struts.apache.org/dtds/struts-2.0.dtd">05<struts>06??? 07??? <!--解决乱码??? -->08??? <constant name="struts.i18n.encoding" value="UTF-8"></constant> 09??? 10??? <package name="simpleton" extends="struts-default,json-default">11??????? 12??????? <action name="*JsonAction" method="{1}" class="com.simpleton.demo.action.JsonAction">13??????????? <result name="fail"></result>14??????????? <!-- 返回json类型数据 -->15??????????? <result type="json">16??????????????? <param name="root">result<!-- result是action中设置的变量名，也是页面需要返回的数据，该变量必须有setter和getter方法 --></param>17??????????? </result>18??????? </action>19??????? 20??? </package>21??? 22</struts>这样就可以完成一个简单json数据类型传递的demo了。