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C#中大数据的存储怎么处理

发布时间: 2013-10-07 19:41:22 作者: rapoo

C#中大数据的存储怎么办?
现在要用C#语言算100的阶层,可100的阶层数据太大。在C#中没有找到想java中BigInteger那样的大数据类型。求高手指点怎么用c#将100的阶层求出来。求代码。标明注释。听说用反射或数组可以做,小弟菜鸟,求解。。。
[解决办法]
仅供参考:

#include <iostream>
#include <string>
#include <algorithm>
using namespace std;
int COMPARE(string number1, string number2) {
int i,j;

int length1 = number1.size();
int length2 = number2.size();

if(number1.size() == 0) number1 = "0";
if(number2.size() == 0) number2 = "0";

j = 0;
for(i = 0; i < length1; ++i) {
if(number1[i] == '0') ++j;
else break;
}
number1 = number1.substr(j);

j = 0;
for(i = 0; i < length2; ++i) {
if(number2[i] == '0') ++j;
else break;
}
number2 = number2.substr(j);

length1 = number1.size();
length2 = number2.size();

if(length1 > length2) {
return 1;
} else if(length1 == length2) {
if(number1.compare(number2) > 0) {
return 1;
} else if(number1.compare(number2) == 0) {
return 0;
} else {
return -1;
}
} else {
return -1;
}

return 0;
}
string PLUS(string number1,string number2) {
int i;
int length1 = number1.size();
int length2 = number2.size();

string result="";

reverse(number1.begin(), number1.end());
reverse(number2.begin(), number2.end());

for(i = 0; i < length1 && i < length2; i++) {
char c = (char)(number1[i] + number2[i] - 48);
result = result + c;
}

while(i < length1) {
result = result + number1[i];
++i;
}

while(i < length2) {
result = result + number2[i];
++i;
}

int carry = 0;
for(i = 0; i < (int)result.size(); ++i) {
int value = result[i] - 48 + carry;
result[i] = (char)(value % 10 + 48);
carry = value / 10;
}

if(carry !=0 ) {
result = result + (char)(carry + 48);
}

for(i = result.size() - 1; i >= 0; i--) {
if(result[i] != '0') break;
}

result = result.substr(0, i + 1);

reverse(result.begin(), result.end());
if(result.length() == 0) result = "0";
return result;


}
string MINUS(string number1,string number2) {
int i;
string result = "";

int length1 = number1.size();
int length2 = number2.size();

if(COMPARE(number2,number1) > 0) {
return "-" + MINUS(number2, number1);
}

reverse(number1.begin(),number1.end());
reverse(number2.begin(),number2.end());

for(i = 0; i < length1 && i < length2; i++) {
char c = number1[i] - number2[i] + 48;
result = result + c;
}

if(i < length1) {
for(; i < length1; i++) {
result = result + number1[i];
}
}

int carry = 0;
for(i = 0; i < (int)result.length(); i++) {
int value = result[i] - 48 + carry;
if(value < 0) {
value = value + 10;
carry = -1;
} else carry = 0;
result[i]=(char)(value + 48);
}

for(i = result.size() - 1; i >= 0; i--) {
if(result[i] != '0')break;
}

result = result.substr(0, i+1);

reverse(result.begin(), result.end());
if(result.length()==0) result = "0";
return result;
}
string MULTIPLY(string number1, string number2) {
int i, j;
int *iresult;
int length1 = number1.size();
int length2 = number2.size();
string result = "";

reverse(number1.begin(), number1.end());
reverse(number2.begin(), number2.end());

iresult = (int*)malloc(sizeof(int) * (length1 + length2 + 1));
memset(iresult, 0, sizeof(int) * (length1 + length2 + 1));

for(i = 0; i < length1; i++) {
for(j = 0; j < length2; j++) {
iresult[i+j] += ((number1[i] - 48) * (number2[j] - 48));
}
}

int carry = 0;
for(i = 0; i < length1 + length2; i++) {
int value = iresult[i] + carry;
iresult[i] = value % 10;
carry = value / 10;
}

for(i = length1 + length2 - 1; i >= 0; i--) {
if(iresult[i] != 0)break;
}

for(; i >= 0; i--) {
result = result + (char)(iresult[i]+48);
}

free(iresult);

if(result == "") result = "0";
return result;
}
string factorial(string n) {
string temp = "1";
string i;
for(i = "1"; COMPARE(i, n) <= 0; i = PLUS(i, "1")) {
temp = MULTIPLY(temp, i);
}
return temp;
}
int main(void) {
cout << factorial("100") << endl;
return 0;
}

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