hibernate 查询出错-

hibernate 查询语句：
userid 字段参照的是 UserInfo 表里面的主键，在我发hql语句就报错了，求解~

@Override
public List<Address> getallAddress(int userid) {

System.out.println(" ---get all address ---");

Query query = sessionFactory.openSession().createQuery(
"select * from t_Address  where userid=?");
query.setParameter(0, userid);

List<Address> list = query.list();
return list;
}

错误：
Struts Problem Report
Struts has detected an unhandled exception:

Messages: unexpected token: * near line 1, column 8 [select * from t_Address where userid=?]
File: org/hibernate/hql/ast/QuerySyntaxException.java
Line number: 54


--------------------------------------------------------------------------------

Stacktraces
org.hibernate.hql.ast.QuerySyntaxException: unexpected token: * near line 1, column 8 [select * from t_Address where userid=?]
org.hibernate.hql.ast.QuerySyntaxException.convert(QuerySyntaxException.java:54)
org.hibernate.hql.ast.QuerySyntaxException.convert(QuerySyntaxException.java:47)
org.hibernate.hql.ast.ErrorCounter.throwQueryException(ErrorCounter.java:82)
org.hibernate.hql.ast.QueryTranslatorImpl.parse(QueryTranslatorImpl.java:284)
org.hibernate.hql.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:182)
org.hibernate.hql.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:136
java? hibernate hql
[解决办法]
而且不支持 * ，你直接写的sql ,当然不行

应该 SELECT o FROM className o WHERE o.xx = :xx
o，其实相当于是一个对象，className 是一类。


[解决办法]
用混淆了不啊