Arduino 模拟信号的读入并转化为0-5V电压
int ledIn = A0;void setup(){ Serial.begin(9600);}void loop(){ int sensorValue = analogRead(ledIn); // 将模拟信号转化为0-5V的电压 float voltage = sensorValue * (5.0 / 1023.0); // 打印电压 if(voltage>1) Serial.println(voltage);}发布时间: 2013-10-30 12:56:21 作者: rapoo
Arduino 模拟信号的读入并转化为0-5V电压
int ledIn = A0;void setup(){ Serial.begin(9600);}void loop(){ int sensorValue = analogRead(ledIn); // 将模拟信号转化为0-5V的电压 float voltage = sensorValue * (5.0 / 1023.0); // 打印电压 if(voltage>1) Serial.println(voltage);}