【类型转换】string 转成 int
收到一个存有ip的指针，我放到了string里面。
例如：

char s_ip[16];
char* p = s_ip;
string ip;
string::iterator it_ip;

memcpy(s_ip, _tip+1, _tip->abtLen-sizeof(TIP_HEAD));//tip包中为ip，写给s_ip
ip = s_ip;//此时我想检索出ip的最后一位
//e.g. 192.163.1.121  取出121转换成int型 

我如何实现取出121并转换成int型，
[解决办法]

std::string ip ="192.163.1.121";
std::stringstream s(ip);
int a,b,c,d; //to store the 4 ints
char ch; //to temporarily store the '.'
s >> a >> ch >> b >> ch >> c >> ch >> d;
std::cout << a << "  " << b << "  " << c << "  "<< d;

[解决办法]
sscanf(s_ip,"%d.%d.%d.%d",&a,&b,&c,&d )
[解决办法]

int a[4] = {0}
sscanf(s_ip, "%d.%d.%d.%d", &a[0], &a[1], &a[2], &a[3]);

//a[0] = 192 
//a[1] = 163 
//a[2] = 1 
//a[3] = 121