能不能把带参数的委托的lambda 表达式改成2个参数的？
static Func<double, object> MakeAddNumber(double numberToAdd)
{
return x =>
{
try
{
return x + numberToAdd;
}
catch (Exception ex)
{
return double.NaN;
}
};
}

类似改成这样：
static Func<double,double, object> MakeAddNumber(double numberToAdd)
{
return x = (d1,d2) =>
{
try
{
return d1 + d2 + numberToAdd;
}
catch (Exception ex)
{
return double.NaN;
}
};
}

不太懂lamda表达式，红色的编译不通过。如果不带numberToAdd参数，能从网上找到例子，带参数的就不会了


[解决办法]
static Func<double,double, object> MakeAddNumber(double numberToAdd)
{
return (d1,d2) =>
{
try
{
return d1 + d2 + numberToAdd;
}
catch (Exception ex)
{
return double.NaN;
}
};
}
[解决办法]
return (d1,d2) =>