求助如何用正则表达式获取字符串中两区间内容
内容是这些
Public Function Showit(ByVal tt As string)
msgbox tt
End Function

Public Function Setit(ByVal tt2 As string)
text1.text=tt2
End Function

我想获取到Showit和Setit

自己试了下用这句Function(.*?)ByVal，但获取的内容确实
Function Showit(ByVal
Function Setit(ByVal
万分感谢您的帮助 vb正则
[解决办法]

'此代码由“正则测试工具  v1.1.35”自动生成，请直接调用TestReg过程
Private Sub TestReg()
    Dim strData As String
    Dim reg As Object
    Dim matchs As Object, match As Object

    strData = "Public Function Showit(ByVal tt As string)"  &  vbCrLf  & _
              "msgbox tt"  &  vbCrLf  & _
              "End Function"  &  vbCrLf  & _
              "Public Function Setit(ByVal tt2 As string)"  &  vbCrLf  & _
              "text1.text=tt2"  &  vbCrLf  & _
              "End Function"

    Set reg = CreateObject("vbscript.regExp")
    reg.Global = True
    reg.IgnoreCase = True
    reg.MultiLine = True
    reg.Pattern = "Function (.*?)\(ByVal"
    Set matchs = reg.Execute(strData)
    For Each match In matchs
        'Debug.Print match.Value
        Debug.Print match.SubMatches(0)
    Next
End Sub

[解决办法]
(?<=Function\s).*?(?=ByVal)
[解决办法]
(?<=Function\s)w+?(?=ByVal)
[解决办法]
版主没有将括号考虑在内哦，你试试这个“(?<=Function\s)\w+(?=\(ByVal)”。