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Js容易判断四则运算是否可用

发布时间: 2014-01-15 15:40:23 作者: rapoo

Js简单判断四则运算是否可用
function?test(s){?????try{????????return?!isNaN(eval("("+s+")"));????}catch(e){????????return?false;????}}alert(test("1+6*(2+(3-1)/1+(9-5*1))"));//--------------------------------------------------------------------------------------<script>var?str?=?"1+6*(2+(3-1)/1+(9-5*1))";try{????eval("var?ret?=?"+str);????if(ret!=Infinity){????????alert("right");????}else{????????alert("wrong");????}}catch(e){????alert("wrong");}</script>//--------------------------------------------------------------------------------------function?test(s){????var?reg=/[\d\.\+\-\*\/\(\)]+/;????try{????????return?ret.test(s)&&!isNaN(eval("("+s+")"));????}catch(e){????????return?false;????}}alert(test("1+6*(2+(3-1)/1+(9-5*1))"));//--------------------------------------------------------------------------------------<script>var?s?=?'1+6*(2+(3-1)/1+(9-5*1))';if(s.match(/[^\+\-\*\/0-9()]/)){????alert('illegal!')}else{????try????{????????alert(eval(s));????}????catch(e)????{????????alert('illegal')????}}</script>

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